Newton's Laws of Motion (Is my theory correct?)

Click For Summary
SUMMARY

The discussion centers on calculating the acceleration of two equal mass carts pushed apart by a spring with a force of 14 N. Each cart, with a mass of 2.0 kg, experiences the full force of 14 N, leading to an acceleration of 7 m/s² for each cart. The application of Newton's second law, F=ma, confirms that the acceleration must be calculated using the total force acting on each cart. Additionally, it is emphasized that acceleration is a vector quantity, requiring direction specification.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Familiarity with the formula F=ma (Force equals mass times acceleration)
  • Basic knowledge of vector quantities
  • Concept of center of mass in physics
NEXT STEPS
  • Study the implications of vector quantities in physics
  • Explore the concept of center of mass in multi-body systems
  • Learn about the effects of forces in opposite directions
  • Investigate real-world applications of Newton's Laws of Motion
USEFUL FOR

Students studying physics, educators teaching Newton's Laws, and anyone interested in understanding the dynamics of forces and motion in mechanical systems.

math989
Messages
5
Reaction score
0

Homework Statement


If two cars of equal mass are pushed apart by a spring mounted on cart #1 with a force of 14 N what will be the resulting acceleration of the carts.

Mass of carts 1 and 2= 2.0Kg
f=14N
A?

Homework Equations


F=ma

The Attempt at a Solution


My theory is that the Newtons will be distributed between the two carts so that each cart will receive 7N of force. Then i can apply f=ma to solve for the A so 7/2= 3.5m/s^2
 
Physics news on Phys.org
I think you've discovered the center of mass coordinate system for this problem.

Since both carts have the same mass and the spring is pushing the, apart then you
Insight is correct.

Remember that acceleration is a vector so to be absolutely correct you must specify a direction too for each carts acceleration.
 
"Pushed apart with a force of 14 N" means that each cart experiences a force of 14 N.
If they were pushed each by 7 N, there would be no reason to add the 7 by 7 and give a value of 14. The two forces are opposite so their sum is zero and not 14.
 

Similar threads

Replies
44
Views
4K
Replies
13
Views
3K
  • · Replies 42 ·
2
Replies
42
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
10K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K