A flat-topped toy cart moves on frictionless wheels, pulled by a rope under tension The mass of the cart is m1. A load of mass m2 rests on top of the cart with the coefficient of static friction u between the cart and the load. The cart is pulled up a ramp that is inclined at an angle theta above the horizontal. The rope is parallel to the ramp. What is the maximum tension T that can be applied without causing to load to slip?(adsbygoogle = window.adsbygoogle || []).push({});

Okay. I figure this problem is fairly simple right?

(i) Fx = m2a

(ii) ff = m2a

(iii)Fy = 0

(iv)Fn - m2gcos = 0

(v) Fn = m2gcos

Plug v into (ii)

(vi) um2gcos = m2a

(vii) a = ugcos

Now sum forces for the cart

(vii) T - ff = (m1+m2)a

Plug in (vi) and (vii)

T - um2gcos = (m1+m2)(ugcos)

Here's my problem. The final answer is simply T = (m1+m2)(ugcos). Meaning there's an obvious problem with my work here...

What's the problem here? I'm so confused!! My teacher suggested "adding m2gsin" to my fx equation, so like m2a + m2gsin? Because I tried that out and it still didn't work. Any help is great help, thanks in advance

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# Homework Help: Newton's laws,solving for tension (smthn wrong with my work)?

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