Newton's method (intersection points)

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SUMMARY

The discussion focuses on using Newton's Method to approximate the intersection points of the functions y = ln(x) and y = (x^2)/8 - 2. The user derived the function f(x) = ln(x) - (x^2)/8 + 2 and its derivative f'(x) = 1/x - x/4. Starting with an initial guess of x1 = 5.4, the user calculated subsequent values, converging towards an intersection point. The consensus is to continue calculations until the results stabilize to four decimal places before rounding to three decimal places for accuracy.

PREREQUISITES
  • Understanding of Newton's Method for root-finding
  • Knowledge of logarithmic and polynomial functions
  • Ability to compute derivatives
  • Familiarity with numerical approximation techniques
NEXT STEPS
  • Implement Newton's Method in Python using libraries like NumPy
  • Explore the convergence criteria for Newton's Method
  • Learn about error analysis in numerical methods
  • Study the graphical interpretation of function intersections
USEFUL FOR

Students in calculus or numerical analysis, mathematicians interested in approximation methods, and anyone looking to understand the application of Newton's Method in finding function intersections.

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Homework Statement



Given two functions; y= ln(x) and y=(x^2)/8 - 2

Use Newton's Method to approximate all intersection points of the given functions, each with 3 decimal places.

Homework Equations



Xn+1 = Xn - f(x) / f`(x)

The Attempt at a Solution



Step 1: I equated the two equations, and I got

f(x) = ln(x) - (x^2)/8 +2

Step 2: I found the derivative as f`(x) = 1/x - x/4

Step 3: then I drew the graphs, and I found that they only intersect at a point near 5.4 (because ln(x) doesn't have any graph in the -x direction)

so I started off x1 = 5.4 and then using the equation given above I found the following values:

X2 = 5.435
X3 = 5.436
X4 = 5.435
X5 = 5.436


Can you guys please tell me if I did the solution right and at which point do I stop ... they keep going ... I'm not going same 3 decimal places for any of them ?
I hope someone would answer soon because I have it due tomorrow early morning. Thanks and can you also tell that whatever I did was right and nothing else was to be done!

:confused:
Thanks
 
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Yes, you are doing fine with one proviso- if you want the answer correct to 3 decimal places, use more than 3 decimal places, 4 should do, during your calculation. Continue until the 4 decimal places are the same or at least give the same answer rounded to 3 decimal places.
 

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