Newton's second law and tension

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Homework Help Overview

The problem involves a helicopter lifting two crates with different masses, requiring the calculation of tension in the cables connecting the crates. The subject area pertains to Newton's second law and the forces acting on objects in an accelerating system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss free body diagrams for each crate, questioning the forces acting on them and the application of Newton's second law. There is confusion regarding which calculations apply to which crate and the roles of the tensions in the cables.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problem by suggesting the need to clarify the forces acting on each crate. Some participants express confusion about the calculations and the logic behind them, while others offer insights into the correct setup for the free body diagrams.

Contextual Notes

Participants note that the original poster's calculations may have been misapplied between the two crates, leading to incorrect results. There is an emphasis on ensuring that all forces, including the tension from the cables, are accounted for in the analysis.

warrior2014
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Newton's second law and tension!

Homework Statement



A helicopter is lifting two crates simultaneously. One crate with a mass of 139 kg is attached to the helicopter by cable A. The second crate with a mass of 88 kg is hanging below the first crate and attached to the first crate by cable B. As the helicopter accelerates upward at a rate of 1.2 m/s2, what is the tension in each of the two cables (in kN)?

Homework Equations



Fnet=ma

The Attempt at a Solution



I drew a free body diagram and for the first crate (139 kg) I had tension pointing upwards and gravity pointing downwards. So I did the following calculations:

-mg + Ta= ma
Ta= m (a + g)
= 139 (1.2 +9.8)
= 1529 N
= 1.529 kN


For the second crate (88 kg), I had tension of the second crate pointing upwards, tension of the first crate pointing downwards and gravity pointing downwards. So I did the following calculations:

-mg- 1529 + Tb= ma
Tb= ma + mg + 1529
= m (a+g) + 1529
= 88 (1.2 + 9.8) + 1529
= 2497 N
= 2.497 kN

Both answers were wrong so I'm not so sure what I'm supposed to be doing for this question. Any help will be appreciated!
 
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warrior2014 said:
I drew a free body diagram and for the first crate (139 kg) I had tension pointing upwards and gravity pointing downwards.

Are you sure that those are all of the forces acting on crate A? After all, it has a rope (that is in tension) attached to the bottom of it as well...
 


The first crate is the one with two tensions acting on it (Cable A and Cable B). The second crate is only attached to Cable B. Do the second crate first!
 


So the calculations I did for crate A should actually be for crate B? and the calculations I did for crate B should be for crate A?
 


warrior2014 said:
So the calculations I did for crate A should actually be for crate B? and the calculations I did for crate B should be for crate A?

Sort of. Your logic was swapped. But don't just reverse the numbers. They will change when you redo it.
 


If I'm not only supposed to reverse the numbers then how exactly am I supposed to solve this problem??
 


warrior2014 said:
If I'm not only supposed to reverse the numbers then how exactly am I supposed to solve this problem??

Exactly as you were intending to solve it. Draw a free body diagram for crate B. Solve for the forces on it. Draw a free body diagram for crate A. Do the same.

What, specifically, is the source of your confusion?
 


I understand how to go about doing the question now. thank you for all of your help :)
 

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