Newton's second law integration

In summary, to integrate the equation \frac{mdv}{F(v)} = dt, the velocity is the derivative of position and the mass is constant. The dt is obtained by rearranging Newton's second law, F(v) = mv'. The prime in the equation with the integral is just another variable for integration. The integral of dt is t, and it can be rewritten as t_final. To solve for v, the integral can be rearranged to get rid of the integral and then solved for v as a function of t. In the special case where F(v) = Fo, a constant, the constant can be plugged into
  • #36
Typo. my bad

v = F(o)t / m + V(o) ?
 
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  • #37
Oblio said:
Typo. my bad

v = F(o)t / m + V(o) ?

yup.
 
  • #38
So... why is this especially significant? They want to see some kind of comment.
Something to do with velocity dependence?
 
  • #39
Oblio said:
So... why is this especially significant? They want to see some kind of comment.
Something to do with velocity dependence?

What kind of motion is it?

v = F(o)t / m + V(o)

describe the kind of motion the object is undergoing.
 
  • #40
the motion would be linear i believe
 
  • #41
Oblio said:
the motion would be linear i believe

Yes, velocity is changing linearly. What about the acceleration?
 
  • #42
YES! your back :)
um...

increasing with time?
 
  • #43
Oblio said:
YES! your back :)
um...

:)

increasing with time?

nope.
 
  • #44
also constant?
 
  • #45
Oblio said:
also constant?

yes. compare:

v = v0 + at

with

v = v0 + (Fo/m)t

the equations have the same form.
 
  • #46
O ya!
I can say both are linear then?
 
  • #47
Oblio said:
O ya!
I can say both are linear then?

Well, linear with constant acceleration. Linear just means the object moves along a straight line.
 
  • #48
Yeah, understood.
 

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