Newton's Second Law - Machine Problem

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SUMMARY

The discussion focuses on calculating the initial acceleration of a 760g steel shuttle pulled by an elastic cord with a tension of 16.0N at a 45º angle. The key equations utilized are ΣF_x = n_x + T_x + F_Gx + f_kx = ma_x and ΣF_y = n_y + T_y + F_Gy + f_ky = ma_y. By resolving the forces into their components, participants conclude that the acceleration can be determined using the component of the tension acting along the steel rail after the cord is released.

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JeYo
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A machine has an 760g steel shuttle that is pulled along a square steel rail by an elastic cord . The shuttle is released when the elastic cord has 16.0N tension at a 45º angle. What is the initial acceleration of the shuttle?

Here is the only photo associated with this problem:knight_Figure_05_59.jpg


Now I think the only equations necessary are \SigmaF_x = n_x + T_x + F_Gx + f_kx = ma_x and \SigmaF_y = n_y + T_y +F_Gy + f_ky = ma_y.



I thought that I could use those two equations in tandem and use the values for a_x and a_y as the a and b sides of a the right triangle whose hypotanuse of which is the answer to the problem and lies along the cord that pulls the shuttle.
 
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I think all you'll need to do for this problem is resolve the force and use the component acting along the steel rail to find the acceleration after the cord is released.
 

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