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Newton's second law of motion

  1. Oct 17, 2013 #1
    1. The problem statement, all variables and given/known data
    If m1=m2=1.0 kg and θ=30°, what will be the acceleration of the system? Calculate the tension in the cord, if a block m1 lying on a frictionless inclined plane and is connected to a mass less cord. Assume m1 is moving down the plane for A), and for B) m1 is in the opposite direction. C) If m1= 1 kg and θ=30°, and the system remains at rest, what must the mass of m2 be? Calculate the tension.

    2. Relevant equations

    ƩF=ma

    3. The attempt at a solution

    For part A
    I have this so far
    m1 x: ƩF=mg(sin30°)-T=ma
    T=mg(sin 30°)/ma
    y: ƩF=N-mg(cos 30°)=0
    N=mg(cos 30°)
    m2 y: T-mg=ma
    T=ma+mg
    T1=T2
    therefore, ma+mg=(g(sin 30°))/a
    so to solve for a I end up getting
    a2+ ga - gsin30°=0
    so do I just do the quadratic formula here or am I going the wrong way about it?

    Here's the problem if you need to see the picture

    http://imageshack.us/f/812/ue4y.jpg/

    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 17, 2013 #2
    No need for the quadratic formula. look at your Forces in the direction. You made a mistake.
     
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