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## Homework Statement

If m

_{1}=m

_{2}=1.0 kg and θ=30°, what will be the acceleration of the system? Calculate the tension in the cord, if a block m

_{1}lying on a frictionless inclined plane and is connected to a mass less cord. Assume m

_{1}is moving down the plane for

**A)**, and for

**B)**m

_{1}is in the opposite direction.

**C)**If m

_{1}= 1 kg and θ=30°, and the system remains at rest, what must the mass of m

_{2}be? Calculate the tension.

## Homework Equations

ƩF=ma

## The Attempt at a Solution

For part A

I have this so far

m

_{1}x: ƩF=mg(sin30°)-T=ma

T=mg(sin 30°)/ma

y: ƩF=N-mg(cos 30°)=0

N=mg(cos 30°)

m

_{2}y: T-mg=ma

T=ma+mg

T

_{1}=T

_{2}

therefore, ma+mg=(g(sin 30°))/a

so to solve for a I end up getting

a

^{2}+ ga - gsin30°=0

so do I just do the quadratic formula here or am I going the wrong way about it?

Here's the problem if you need to see the picture

http://imageshack.us/f/812/ue4y.jpg/