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Newton's second law of motion

  • Thread starter anim8or
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  • #1
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Homework Statement


If m1=m2=1.0 kg and θ=30°, what will be the acceleration of the system? Calculate the tension in the cord, if a block m1 lying on a frictionless inclined plane and is connected to a mass less cord. Assume m1 is moving down the plane for A), and for B) m1 is in the opposite direction. C) If m1= 1 kg and θ=30°, and the system remains at rest, what must the mass of m2 be? Calculate the tension.

Homework Equations



ƩF=ma

The Attempt at a Solution



For part A
I have this so far
m1 x: ƩF=mg(sin30°)-T=ma
T=mg(sin 30°)/ma
y: ƩF=N-mg(cos 30°)=0
N=mg(cos 30°)
m2 y: T-mg=ma
T=ma+mg
T1=T2
therefore, ma+mg=(g(sin 30°))/a
so to solve for a I end up getting
a2+ ga - gsin30°=0
so do I just do the quadratic formula here or am I going the wrong way about it?

Here's the problem if you need to see the picture

http://imageshack.us/f/812/ue4y.jpg/

Homework Statement





Homework Equations





The Attempt at a Solution


Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
47
0
No need for the quadratic formula. look at your Forces in the direction. You made a mistake.
 

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