If m1=m2=1.0 kg and θ=30°, what will be the acceleration of the system? Calculate the tension in the cord, if a block m1 lying on a frictionless inclined plane and is connected to a mass less cord. Assume m1 is moving down the plane for A), and for B) m1 is in the opposite direction. C) If m1= 1 kg and θ=30°, and the system remains at rest, what must the mass of m2 be? Calculate the tension.
The Attempt at a Solution
For part A
I have this so far
m1 x: ƩF=mg(sin30°)-T=ma
y: ƩF=N-mg(cos 30°)=0
m2 y: T-mg=ma
therefore, ma+mg=(g(sin 30°))/a
so to solve for a I end up getting
a2+ ga - gsin30°=0
so do I just do the quadratic formula here or am I going the wrong way about it?
Here's the problem if you need to see the picture