NMR signals for a benzene ring with methyl and chlorine ortho to each other

[FTNMR]

How many NMR signals and peaks will there be for a di-substituted benzene ring and why?
The ring has one CH3 and and a Cl ortho to the CH3.

(This isn't a homework problem but I am running into same issue whenever I encounter rings wrt NMR)

i am specifically confused as to how to apply the n+1 rule to determine the number of peaks, with respect to two chemically equivalent protons.

But first the signals

On the above example, I think there will be 3 signals:
the 3 chemically equivalent methyl protons = signal 1
the 2 chem equiv protons on either side of the Cl = the 2nd signal
the 2 chem equiv protons on either side of the methyl = the 3rd signal

Before I ask about peaks, could someone tell me if this is correct so far?

thanks

 

[Ygggdrasil]

You say that the methyl is ortho to the chlorine, but from the description of the protons, it sounds like you're talking about p-chlorotoluene where the groups are para to each other. Which is correct?

 

[FTNMR]

 

[FTNMR]

You say that the methyl is ortho to the chlorine, but from the description of the protons, it sounds like you're talking about p-chlorotoluene where the groups are para to each other. Which is correct?

Sorry not sure why i said ortho, yup i definitely meant para..heres drawing so its clear

 

[FTNMR]

please ignore that little grey dot above the ring.. no idea what that is (just learning chemdoodle).. thanks

 

[Borek]

Three kinds of protons sounds right.