No idea how to compute this limit

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SUMMARY

The limit in question is \lim_{x→-∞}xe^{x}, which can be computed by rewriting it as \lim_{x→-∞} \frac{x}{e^{-x}}. To solve this limit, L'Hôpital's rule is applied, which is a method for evaluating limits of indeterminate forms. By differentiating the numerator and denominator, the limit can be resolved effectively.

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Bipolarity
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Homework Statement



[tex]\lim_{x→-∞}xe^{x}[/tex]

Homework Equations


The Attempt at a Solution



L'Hopital's rule maybe? I solved a lot of problems today, just no idea how to get past this one. Any hints?

BiP
 
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Write the limit as
[tex]\lim_{x→-∞} \frac{x}{e^{-x}}[/tex]
Apply L'Hopital's rule.
 
Pranav-Arora said:
Write the limit as
[tex]\lim_{x→-∞} \frac{x}{e^{-x}}[/tex]
Apply L'Hopital's rule.

Thank you so much!

BiP
 

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