No idea what the textbook is doing

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phospho
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I mean, I used a similar method as they're using, but I didn't get their answer at all. Where did the x-4 come from? (I used x-6), also, I got d = (6-x)tan50 and d = xtan(3) solving this to get x = 4.04
 
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  • Solution diagram for a rod AB with two strings: forces TA and TB meet at a point below the rod, angles 30 and 50 degrees marked, distance x from A and 4-x from B labelled, with the 4g weight shown beneath.
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phospho said:
I mean, I used a similar method as they're using, but I didn't get their answer at all. Where did the x-4 come from? (I used x-6), also, I got d = (6-x)tan50 and d = xtan(3) solving this to get x = 4.04

Looks like the book's solution is incorrect on two counts. First, the problem statement has changed at some point to have 6m as the length of the rod, while the solution assumes it's 4m. Second, I don't see how they can use the sine function since the hypotenuse's of the triangles are unknown (and not even labelled). They should use the tan function.