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No. of possible electron transitions in hydrogen in magnetic field

  1. Apr 27, 2014 #1
    1. The problem statement, all variables and given/known data
    A hydrogen atom is in the n=3 state. Given that a magnetic field is present, how many photons of different energy can we observe when the atom de-excites to the ground state?

    2. Relevant equations
    quantum number, angular momentum quantum number, orbital magnetic quantum number

    3. The attempt at a solution
    So far, I am aware in the absence of a magnetic field, there should be three possible transitions: n=3 to n=2, n=3 to n=1, and n=2 to n=1. I know that a magnetic field will cause there to be orbital magnetic quantum number. However, may I know whether electrons in the same n-state but with different angular momentum quantum number and orbital magnetic quantum number have different energy levels? For example, are energy levels of electron in the state: [n=3, l=2, m[itex]_{l}[/itex]=1] different from [n=3, l=2, m[itex]_{l}[/itex]=-1]?
     
    Last edited: Apr 27, 2014
  2. jcsd
  3. Apr 27, 2014 #2

    Simon Bridge

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    Welcome to PF;
    Magnetic fields interact with the electron angular momenta ... thus splitting the energy levels.
    So yes - each angular momentum state now has a unique energy where before you had degenerate states.
    The question is basically testing your knowledge of this ...

    Look up "splitting" and "hyperfine splitting".
    But what I think you really want is "Zeeman Effect".
    http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/zeeman.html
     
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