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-A spherical balloon is inflated to a diameter of 20.0 cm. Assume that the gas in the balloon is of atmospheric pressure (101.3 kPa) and is at a temperature of 20.0 °C. It is then taken by a diver 15.0 m under the sea. The temperature of the seawater at this depth is 16.0 °C . Density of seawater: 1030. kg m–3. The gauge pressure of the air in the balloon at this depth is 27300Pa.
Q1>Assuming the gas in the balloon is in thermal equilibrium with seawater, what is the volume of the balloon now?
-Steam at 100 °C is mixed with 166.4 g of ice at –32.8 °C, in a thermally insulated container, to produce water at 44.6 °C. Ignore any heat absorption by the container.
-Cwater = 4186. J/(kg °C)
-Cice = 2090. J/(kg °C)
-Lf,water = 3.33 × 105 J/kg
-Lv,water = 2.26 × 106 J/kg
Also,energy is required to bring all the ice up to 0 °C=11400J;
energy is required to melt the ice into water at 0 °C=55400J;
energy required to raise the temperature of this melted water to 44.6 °C =31100J;
energy supplied by the steam to change the state of 166.4 g of ice at –32.8 °C to water at 44.6 °C =97884J
Q2>What is the final mass of water in the cup at 44.6 °C??
Thanks in advance !
Q1>Assuming the gas in the balloon is in thermal equilibrium with seawater, what is the volume of the balloon now?
-Steam at 100 °C is mixed with 166.4 g of ice at –32.8 °C, in a thermally insulated container, to produce water at 44.6 °C. Ignore any heat absorption by the container.
-Cwater = 4186. J/(kg °C)
-Cice = 2090. J/(kg °C)
-Lf,water = 3.33 × 105 J/kg
-Lv,water = 2.26 × 106 J/kg
Also,energy is required to bring all the ice up to 0 °C=11400J;
energy is required to melt the ice into water at 0 °C=55400J;
energy required to raise the temperature of this melted water to 44.6 °C =31100J;
energy supplied by the steam to change the state of 166.4 g of ice at –32.8 °C to water at 44.6 °C =97884J
Q2>What is the final mass of water in the cup at 44.6 °C??
Thanks in advance !