- #1
jegues
- 1,097
- 3
So, your final solution is correct except for a wrong sign on V2.
jegues said:Why is V2 negative?
Zryn said:The voltage (difference in potential) dropped across a resistor is equal to the higher potential minus the lower potential divided by the resistance.
The Electrician said:If you're calculating the currents leaving a node, call it Vx, then if a resistor is connected to another node, Vz perhaps, the resistor current is (Vx-Vz)/R. If the resistor is connected to ground then Vz is automatically zero, so the current is (Vx-0)/R = Vx/R.
Zryn said:Your fraction is incorrect. Keep in mind voltages in series add together.
What is the voltage on the left of the Resistor??
What is the voltage on the right of the Resistor?
Not every component is a voltage immediately in series with another voltage however.
Zryn said:Exactly!
Now you should be able to conquer most voltage dividers easily ;).