# How to analyze a circuit with one node using the node method

## Homework Statement

I have the circuit given below with a single node where R3 and ground meet. How can I solve this problem using the inspection method? Is it possible? I can easily solve using another method but I would rather try using the inspection method.

## Homework Equations

Ax = M
A is the resistance matrix obtained via inspections
x is the voltage matrix
M is the current matrix

## The Attempt at a Solution

Since there is only one node then my resistance matrix, obtained using inspection, will only have one row and one column. Thus in this case:

A = [ 17000]

The voltage matrix will only have my one at the node:

x = [V]

finally the current matrix will have the sum of all the current sources going into the node (subtract those going away):

M = [1mA + 1mA] = [2mA]

I can take the inverse of A and then multiply it by M to get:

x = A^-1 * M
or
V = 2mA/17000
which i believe is the wrong answer. Am I wrong? Can I even solve this using inspection since it is only one node? Thanks. #### Attachments

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gneill
Mentor
Since this is nodal analysis you'll want the conductance matrix, not the resistance matrix. Those current sources appear to be 1 Amp each, not one milliamp each.

• scottdave
Since this is nodal analysis you'll want the conductance matrix, not the resistance matrix. Those current sources appear to be 1 Amp each, not one milliamp each.
OMG I totally forgot about that! Thank you Thank you!