Non-Headon Collision Vector Representation

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Discussion Overview

The discussion centers on the mechanics of non-head-on collisions between two objects of similar mass, particularly focusing on why such collisions can result in a 90-degree separation of the objects post-collision. Participants seek to represent this phenomenon in vector form and explore the conditions under which this occurs.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions the mechanics behind a non-head-on collision resulting in a 90-degree split, specifically when one object has momentum and the other does not.
  • Another participant notes that for the 90-degree separation to occur, certain conditions must be met: the objects should be of equal mass, the collision must be elastic, and they should be free to move in any direction on a plane.
  • Some participants acknowledge these conditions as assumptions necessary for the discussion.
  • There are requests for vector calculations to illustrate the scenario, with references to previous posts that may contain relevant equations and explanations.
  • One participant suggests writing down the x and y components of momentum and energy to solve the equations, referencing a specific post for further guidance on the mathematical relationships involved.

Areas of Agreement / Disagreement

Participants generally agree on the conditions required for the 90-degree separation to occur, but the exact mechanics and calculations remain unclear to some, indicating that multiple views and uncertainties persist regarding the vector representation and outcomes of the collision.

Contextual Notes

The discussion does not resolve the mathematical steps necessary to demonstrate the 90-degree separation, and the assumptions regarding the conditions of the collision are not fully explored.

shredder666
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Why does a non head on collision between objects with momentum and an object without momentum result in a 90 degree split? (objects have similar mass)

Could you please represent this in vector form? I'm not sure how I could represent this because it's not a head on collision but a side swipe...
 
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Normallly the objects have to be the same size, and there can be no losses in the collision (elastic collision), and the objects have to be free to travel in any direction, at least any direction on a plane.
 


well yea those conditions are assumed
 


I still don't get how the collision results in a 90 degree angle, could someone show me some vector calculation with variables
 


shredder666 said:
I still don't get how the collision results in a 90 degree angle, could someone show me some vector calculation with variables
You have to write down the x and y components of momentum and energy, and solve the equations, See Andy Mason's post #5 in
https://www.physicsforums.com/showthread.php?t=311193&highlight=collision+equal+mass
and determine what kind of triangle with sides A, B, and C (if any) satisfies the relation A2+B2 = C2.
 


oh ok thanks
 

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