Non-Homogeneous Heat Equation (Insulated Bar Question)

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Homework Statement


Find U(x,t)

dU/dt = d2U/dx2 + sin x

Boundary Conditions:
dU/dx (0,t) = 0

and

U(1,t) = 0

Initial Condition: U(x,0) = cos 7*π*x

2. The attempt at a solution

I start off with:
d2(Un)/dx2 = λnUn (as an initial value problem)

[d(Un)/dx](0) = 0; [d(Un)/dx](1) = 0

My teacher told me to use the orthogonality later on, but at this point I'm stuck.
Can anyone enlighten me? Thanks!
 
ok, so so far you have assumed separatino of variables, that is u(x,t) = U(x)T(t) and

so now you'll need to find the eigenfunctions of the homogenous boundary value problem
[tex]U_n''(x) = \lambda_n U_n(x)[/tex]
[tex]U_n(0) = 0[/tex]
[tex]U_n'(1) = 0[/tex]

now solve the ODE above for 3 separate cases λn <0, =0, >0 and see which values of λn are allowable for the given boundary conditions. This yields the eigenvalues & eigenfunctions for the boundary value problem.
 
lanedance said:
ok, so so far you have assumed separatino of variables, that is u(x,t) = U(x)T(t) and

so now you'll need to find the eigenfunctions of the homogenous boundary value problem
[tex]U_n''(x) = \lambda_n U_n(x)[/tex]
[tex]U_n(0) = 0[/tex]
[tex]U_n'(1) = 0[/tex]

now solve the ODE above for 3 separate cases λn <0, =0, >0 and see which values of λn are allowable for the given boundary conditions. This yields the eigenvalues & eigenfunctions for the boundary value problem.

I get like [tex]U_n = cos(n \pi x)[/tex] and [tex]\lambda _n = -(n \pi)^2[/tex]
Is that correct?
 
do they satisfy you boundary conditions?

look ok for the 2nd, not so sure about the first
 

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