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Homework Statement
Someone did an experiment with an ideal voltmeter and an ideal ampermeter using the circuit in the picture, and got the graph in the picture.
We know use an unideal voltmeter, how will the graph change?
We know use an unideal ampermeter (the voltmeter is ideal), how will the graph change?
Homework Equations
V=IR
u=VIr
The Attempt at a Solution
The graph basically displays u=εIr.
I figured that if the voltmeter is not ideal, the same current measured by the ampermeter will be "shared" by the voltmeter and the resistor, causing a higher value for the same current. In the answers they say it won't change.
Then, I figured that if the ampermeter is not ideal, the value will decrease quicker, becuase now u=εIrIR, this one doesn't have an answer.
Where is my mistake? Am I right?
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