Non-linear ODE: y'=(y-1)^2 + 0.01

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SUMMARY

The discussion focuses on solving the non-linear ordinary differential equation (ODE) given by y' = (y - 1)^2 + 0.01 with the initial condition y(0) = 1. The correct solution is identified as y(x) = 1 + 0.1 Tan(0.1x). The participant attempted to use separation of variables but encountered an algebraic error in their integration process, leading to confusion regarding the appearance of the tangent function in the solution.

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Homework Statement



y' = ( y - 1 )^2 +0.01 y(0)=1


(trying out latex)
[tex]y' = (y-2)^{2} + 0.01; y(0)=1[/tex]

Homework Equations



Separation of variables, Right?

The Attempt at a Solution



The solution is is y(x)=1+0.1 Tan (0.1x)

How did they get this? I did separation of variables and got:

dx = ( 1/(y-1)^2 + 100 )dy

integrating gets:

x = -1/(y-1) +100y + C

Tangent...is not here. What am I doing wrong here?
 
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Check your algebra. You're making a very elementary mistake.
 

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