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- What does a connection that isn't metric compatible mean?
If this is opening a can of worms then please say so and I'll start a separate thread.Orodruin said:- The connection should be metric compatible.
This constraint on the covariant derivative means that transporting the metric is, in fact, path independent. Is this actually a requirement for any physically plausible theory? If you don't impose it, doesn't it mean that a free-falling observer can measure the metric near some event (getting a local Minkowski frame) then find that the theory says that the "natural" transport of that is not a local Minkowski frame at some later event? That is, such a theory wouldn't respect the equivalence principle?
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