Finding the Total Charge of a Non-Uniformly Charged Disc

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SUMMARY

The discussion focuses on calculating the total charge of a non-uniformly charged disc with radius R, where one half has a charge density of +2σ and the other half has -σ. Participants explore the implications of charge distribution, debating whether the division refers to half the radius or half the surface area. The consensus indicates that the charge distribution's interpretation does not affect the total charge calculation, as both configurations yield the same result when properly analyzed.

PREREQUISITES
  • Understanding of electrostatics and charge density concepts
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of the area of a disc and its mathematical representation
  • Basic principles of charge conservation in physics
NEXT STEPS
  • Study the integration of charge density over non-uniform surfaces
  • Learn about the electric field generated by non-uniform charge distributions
  • Explore the concept of charge density in different geometrical configurations
  • Investigate the implications of charge conservation in electrostatics
USEFUL FOR

Physics students, educators, and anyone interested in electrostatics and charge distribution analysis will benefit from this discussion.

Hatyk
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Homework Statement


I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc.

Homework Equations


dQ=ρ2πr^2 I would use this equation if the charge density was uniform

The Attempt at a Solution


My first idea was to split the disc in the middle and find the total charge of each part separately and then add them up. Thinking about it now, this solution feels wrong. What is the correct solution?
 
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Well, in my opinion the statement of problem not say if the half is the half of radius or the half of surface. My intuition says the half of surface, but you can make the two cases
 
Statement of the problem is not complete. Which two halves are we talking about?
 
Hatyk said:

Homework Statement


I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc.

Homework Equations


dQ=ρ2πr^2 I would use this equation if the charge density was uniform

The Attempt at a Solution


My first idea was to split the disc in the middle and find the total charge of each part separately and then add them up. Thinking about it now, this solution feels wrong. What is the correct solution?
I see nothing wrong with your assumption. I'll go on a limb and say it doesn't matter if the charges are all +2s on one side and -s on the obverse side, vs. each side has half +2s and the other half -s.
 
Last edited:
How about half the radius with +2σ and the other half with -σ?
 
Chandra Prayaga said:
How about half the radius with +2σ and the other half with -σ?
Personally I'd have some difficulty justifying that given how the area of a disk varies with the radius :smile:
 
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