Nonconservative/work theorem problem.

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SUMMARY

The problem involves a 98-kg firefighter sliding down a fire pole, experiencing an average frictional force of 780 N, and reaching a speed of 3.4 m/s at the bottom. The relevant work-energy principle equation is Wwc = 1/2mvf² + mghf - 1/2mvo² + mgho. The solution requires calculating the distance slid down the pole by considering the work done by gravity and the work done against friction.

PREREQUISITES
  • Understanding of the work-energy principle
  • Familiarity with non-conservative forces
  • Basic knowledge of kinematics
  • Ability to manipulate equations involving mass, force, and acceleration
NEXT STEPS
  • Calculate the work done by gravity using Wg = mgh
  • Determine the total work done against friction
  • Explore the implications of non-conservative forces in mechanical systems
  • Review kinematic equations to relate speed, distance, and acceleration
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Students studying physics, particularly those focusing on mechanics and energy concepts, as well as educators looking for practical examples of non-conservative forces in action.

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Homework Statement


Starting from rest, a 98-kg firefighter slides down a fire pole. The average frictional force everted on him by the pole has a magnitude of 780 N, and his speed at the bottom of the pole is 3.4 m/s. How far did he slide down the pole?

Homework Equations


Not sure? Maybe, Wwc = 1/2mvf2 + mghf - 1/2mvo2 + mgho

The Attempt at a Solution



I have no idea where to start...
 
Last edited:
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The idea is that we'll ignore the other non-conservative force losses and assume that friction is the one non-conservative force that makes the fireman not fall as if he simply jumped down. So the total work is the work from gravity plus the work from friction.
 

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