Nonhomogeneous linear differential equation

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SUMMARY

The discussion focuses on solving the nonhomogeneous linear differential equation y'' - 6y' + 11y - 6 = e^{4x}. The Wronskian determinant, calculated as W = 10e^{6x}, is utilized along with the method of variations to find particular solutions. The solutions derived include u' = (1/4)e^{8x}, v' = (-1/9)e^{9x}, and w' = (-1/7)e^{7x}. The final integration yields y = (1/10)e^{2x} - (1/30)e^{3x} - (1/10)e^{x}, although the contributor notes a discrepancy in the number of roots.

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Homework Statement


solve for y(x).

[tex]y"'-6y"+11y'-6=e^{4x}[/tex]



Homework Equations



Wronskian determinant. Method of variations.

The Attempt at a Solution

Supposing that [u', v', w'] are the solutions, wronskian det=W is [tex]10e^{6x}[/tex]
By use of [tex]x_k=\frac{det(M_{k})}{det(x)}[/tex], I got [tex]u'=\frac{1}{4}e^{8x},v'=\frac{-1}{9}e^{9x}, w'=\frac{-1}{7}e^{7x}[/tex]. Integration gives [tex]y=\frac{1}{10}e^{2x}-\frac{1}{30}e^{3x}-\frac{e^{x}}{10}[/tex].
 
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The answer has four whereas i came up with only 3 since the roots are 1,2, and 3 respectively. I think [tex]W=2e^{6x}[/tex]
 

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