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Nonuniform line of charge, find the electric potential

  1. Oct 31, 2009 #1
    A nonuniform linear charge distribution given by λ = bx, where b is a constant, is located along an x axis from x = 0 to x = 0.50 m. Suppose that b = 25 nC/m2 and V = 0 at infinity.


    (b) What is the electric potential at the point y = 0.30 m on the y axis?




    E = kq/r^2
    V = -Ed



    Since there's no charge on the y, I think I would have to find the E-field at that point on y, and then use V = -Ed. But how do I integrate the E-field if it's nonuniform?

    And is this what I'm supposed to do?
     
    Last edited: Oct 31, 2009
  2. jcsd
  3. Oct 31, 2009 #2

    rl.bhat

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    Potential at any point is given by
    V = k*Q/r.
    Since charge distribution is nonuniform
    V = Intg[k*dq/r] between x = 0 to x = 0.5 m
    Now dQ = bx*dx and r = sqrt( 0.3^2 + x^2)
    Find the integration.
     
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