Block M(15.7kg) is on a horizontal table initially moving to the left because it is connected to a mass m(8.2kg) hanging vertically off of the edge of the table (left hand side of the table). A force F, with a magnitude of 75.3N, acts on M directed at an angle of 35.0 degrees above the horizontal( to the right hand side of the table). There is no friction and the pulley and string are massless. a)What is the normal force (N) on M? Fn=mg-75.3*sin(35.0)-T Fn-15.7-43.19-52.79 Fn=-80.28?????????????? Or would I first subtract both of the forces acting on M T-F=52.79-43.19=9.6 Fn=15.7-9.6=6.1 b)What is the tension in the string The tension origionally is 52.79 with out the force acting on M would it now be 9.6 c)What is the acceleration of M d) Is the speed of M increasing or decreasing?