(adsbygoogle = window.adsbygoogle || []).push({}); While moving in, a new homeowner is pushing a box across the floor at a constant velocity. The coefficient of kinetic friction between the box and the floor is 0.41. The pushing force is directed downward at an angle θ below the horizontal. When θ is greater than a certain value, it is not possible to move the box, no matter how large the pushing force is. Find that value of θ.

2. Relevant equations

F_{N}= mg + FsinƟ

F_{friction}= 0.41(mg + FsinƟ)

F_{friction}= FcosƟ in our problem.

0.41(mg+FsinƟ) = FcosƟ

0.41mg + 0.41FsinƟ = FcosƟ

I think I am correct and that my logic is sound so far but I just do not see how I can find Ɵ? Hints please?

3. The attempt at a solution

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# Normal force, friction, Newton's law

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