A small rock with mass 0.22 kg is released from rest at point A, which is at the top edge of a large, hemispherical bowl with radius R = 0.60 m (the figure ). Assume that the size of the rock is small compared to R, so that the rock can be treated as a particle, and assume that the rock slides rather than rolls. The absolute value of the work done by friction on the rock, when it moves from point A to point B at the bottom of the bowl, is 0.25 J.
Just as the rock reaches point B, what is the normal force on it due to the bottom of the bowl?
The Attempt at a Solution
I know that its not just the mass times gravity like the normal force usually is because it has a velocity of 3.08 m/s.
I am just not sure how to use this and find the normal force :(