Normalization constant A of a harmonic oscillator

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  • #1
Sorin2225
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Homework Statement:
Finding the normalization constant A of a harmonic oscillator
Relevant Equations:
(psi(x,t))^2=1
media_df0_df08153c-e951-4140-bf30-75ec0c2140b9_phpO7r43W.png
IMG_20200427_121732.jpg


I've worked through it doing what I thought I should have done. I normalized the original wavefunction(x,0) and made it = one before using orthonormality to get to A^2(1-1) because i^2=-1 but my final answer comes out at 1/0 which is undefined and I don't see how that could be correct since A is meant to be a real number. I'm not really sure where I've gone wrong either so any insight would be appreciated.
 

Answers and Replies

  • #2
vela
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##\lvert \psi_1 + i \psi_4 \rvert^2 \ne (\psi_1 + i \psi_4)^2##

The vertical lines matter.
 
  • #3
Sorin2225
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So it's the absolute value? which means that it's +1 not -1?
 
  • #4
vela
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What is “it”?
 
  • #5
Sorin2225
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|iψ4*iψ4|
 
  • #6
vela
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That's not how absolute values work. You can't say ##\lvert a+b \rvert = \lvert a \rvert + \lvert b \rvert## in general.

How do you calculate the modulus of a complex number?
 
  • #7
Sorin2225
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sqrt(a^2+b^2) so it would be Sqrt((i^2)^2+((psi(4)^2)^2))
 
  • #8
kuruman
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##|\Psi|^2=\Psi^*\Psi=[A(\psi_1+i\psi_4)][A^*(\psi^*_1-i\psi^*_4)]##. What do you get when you multiply it out?
 

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