Normalization constant A of a harmonic oscillator

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Homework Help Overview

The discussion revolves around finding the normalization constant A for a harmonic oscillator wavefunction. Participants are exploring the implications of normalization and orthonormality in the context of quantum mechanics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to normalize a wavefunction but encounters an undefined result. Participants question the use of absolute values in complex numbers and discuss the properties of modulus calculations.

Discussion Status

The discussion is active, with participants providing insights into the properties of complex numbers and questioning the original poster's approach. There is no explicit consensus, but various interpretations and clarifications are being explored.

Contextual Notes

Participants are navigating the complexities of quantum mechanics, particularly the normalization of wavefunctions, and are addressing potential misunderstandings related to mathematical operations involving complex numbers.

Sorin2225
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Homework Statement
Finding the normalization constant A of a harmonic oscillator
Relevant Equations
(psi(x,t))^2=1
media_df0_df08153c-e951-4140-bf30-75ec0c2140b9_phpO7r43W.png
IMG_20200427_121732.jpg


I've worked through it doing what I thought I should have done. I normalized the original wavefunction(x,0) and made it = one before using orthonormality to get to A^2(1-1) because i^2=-1 but my final answer comes out at 1/0 which is undefined and I don't see how that could be correct since A is meant to be a real number. I'm not really sure where I've gone wrong either so any insight would be appreciated.
 
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##\lvert \psi_1 + i \psi_4 \rvert^2 \ne (\psi_1 + i \psi_4)^2##

The vertical lines matter.
 
So it's the absolute value? which means that it's +1 not -1?
 
What is “it”?
 
|iψ4*iψ4|
 
That's not how absolute values work. You can't say ##\lvert a+b \rvert = \lvert a \rvert + \lvert b \rvert## in general.

How do you calculate the modulus of a complex number?
 
sqrt(a^2+b^2) so it would be Sqrt((i^2)^2+((psi(4)^2)^2))
 
##|\Psi|^2=\Psi^*\Psi=[A(\psi_1+i\psi_4)][A^*(\psi^*_1-i\psi^*_4)]##. What do you get when you multiply it out?
 

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