Normalize Vector: Steps & Solutions

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To normalize the 1xn vector v=<c,c,c...c>, the correct approach involves dividing by the square root of the sum of the squares of its elements. The formula for normalization is U=V/|V|, where |V| is computed as the square root of the sum of the squares. In this case, since all elements are equal to c, the vector can be simplified to c<1,...,1>. While there are different ways to perform calculations, the explicit method of calculating |v| is recommended for clarity. Understanding this process is essential for accurately normalizing vectors.
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Homework Statement


Normalize the 1xn vector

v=<c,c,c...c>

Homework Equations



U=V/|V|

The Attempt at a Solution



I have a solution to a different question and it says this:
if each element is c, we can normalize it and divide it by the sum of the elements.
So, what they did was
c/(n*c)=1/n

As far as I remember, it needs to be 1/(sqrt(n))

Or, there are different methods to normalize vectors?Thanks.
 
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Roni1985 said:

Homework Statement


Normalize the 1xn vector

v=<c,c,c...c>

Homework Equations



U=V/|V|

The Attempt at a Solution



I have a solution to a different question and it says this:
if each element is c, we can normalize it and divide it by the sum of the elements.

You actually have to divide by the square root of the sum of the squares of the elements.

So, what they did was
c/(n*c)=1/n

As far as I remember, it needs to be 1/(sqrt(n))

Or, there are different methods to normalize vectors?

There aren't really different methods, but it's possible to carry out some calculations in different ways.

First of all, the way that will always work is to just explicitly compute |v| and use the definition of the normalized vector u = v/|v|. In this specific case, v = <c,...,c> = c <1,...,1> by the rules of scalar multiplication, so we can instead just divide by c right here and normalize <1,...,1>.

You seem to be on the right track (your comment about the square root is important), but it's probably worthwhile to just do the calculation explicitly instead of trying to reproduce an example in your notes.
 
fzero said:
You actually have to divide by the square root of the sum of the squares of the elements.



There aren't really different methods, but it's possible to carry out some calculations in different ways.

First of all, the way that will always work is to just explicitly compute |v| and use the definition of the normalized vector u = v/|v|. In this specific case, v = <c,...,c> = c <1,...,1> by the rules of scalar multiplication, so we can instead just divide by c right here and normalize <1,...,1>.

You seem to be on the right track (your comment about the square root is important), but it's probably worthwhile to just do the calculation explicitly instead of trying to reproduce an example in your notes.

I see, thanks for your answer. It was very helpful.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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