Undergrad Normalizing Constant 3D Infinite Well

RaulTheUCSCSlug
Gold Member
Messages
179
Reaction score
28
For time independent Schrödinger's equation in 3-D

Where Enx,ny,nz=(nx/Lx2+ny/Ly2+nz/Lz2)(π2ħ2/2m
and Ψnx,ny,nz=Asin(nxπx/Lx)sin(nyπy/Ly)sin(nzπz/Lz)

How do I normalize A to get (2/L)^3/2?

I don't think I understand how to normalize constants.
 
Physics news on Phys.org
A normalized state ##\psi## means that the total probability described by this state, ##|\psi|^2##, is equal to unity.
 
  • Like
Likes phoenix95 and RaulTheUCSCSlug
So when A is (2/L)^3/2 then |\psi|^2 is equal to one since the probability density must go to one?

So to solve for A one would just go through |\psi|^2 = 1 then solve for A?
 
The integral of ##|\psi^2|## over all space (or equivalently, over the entire volume of the well, since ##\psi## must be zero outside the well) must equal 1 in order for ##\psi## to be normalized.
 
  • Like
Likes RaulTheUCSCSlug
RaulTheUCSCSlug said:
So to solve for A one would just go through |\psi|^2 = 1 then solve for A?
No, not that which must be equal to 1. Take a look at jtbell's comment above.
 
Right. So the purpose is to have the probability of the whole function sum up to 1. Okay. I went to office hours and got things clarified thank you!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
9
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
10K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 3 ·
Replies
3
Views
3K