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Normed spaces and the parallelogram identity

  • Thread starter quasar987
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quasar987
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Homework Statement


My professor stated the theorem "If (X,<,>) is an an inner product space and || || is the norm generated by <,>, then we have ||x+y||² + ||x-y||² = 2(||x||² + ||y||²)." But then she also said that the converse was true. I suppose this means that "Given (X, || ||) a normed space, if it satisfies the parallelogram identity, then the norm is issued from an inner product."

I do not have an idea as to how to prove that converse.
 

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morphism
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