Norms question (parallelogram law)

  • Thread starter Thread starter tourjete
  • Start date Start date
  • Tags Tags
    Law
Click For Summary
SUMMARY

The discussion focuses on the definition of a norm in the context of the vector space C[a,b] with the norm defined as ||f|| = max{|f(x)|, x∈[a,b]}. It is established that this norm does not satisfy the parallelogram law, which is given by ||x-y||² + ||x+y||² = 2||x||² + 2||y||². The participants clarify that the norm defined does not align with inner-product norms, as demonstrated through examples where the norm fails to meet the parallelogram condition.

PREREQUISITES
  • Understanding of vector spaces, specifically C[a,b]
  • Familiarity with the definition and properties of norms
  • Knowledge of the parallelogram law in normed spaces
  • Basic concepts of complex-valued functions
NEXT STEPS
  • Study the properties of norms in functional analysis
  • Learn about inner-product spaces and their characteristics
  • Explore examples of norms that satisfy the parallelogram law
  • Investigate the implications of norms in different vector spaces
USEFUL FOR

Students of mathematics, particularly those studying functional analysis, vector spaces, and norms, as well as educators seeking to clarify the differences between various types of norms.

tourjete
Messages
23
Reaction score
0

Homework Statement


Consider the vector space C[a,b] of all continuous complex-valued functions f(x), x\in [a,b]. Define a norm ||f|| = max{|f(x)|, x\in [a,b]]

a) show that this is a norm
b) Show that this norm does not satisfy the parallelogram law, thereby showing that its not an inner-product norm.

Homework Equations


Parallelogram law: ||x-y||^{2} + ||x+y||^{2} = 2||x||^{2} + 2||y||^{2}

The Attempt at a Solution



I'm mostly having trouble defining the norm. I'm a little unclear on what the concept of a norm is; we only went over inner-product norms in class. I draw the vector going from the origin to the maximum on [a,b] and to define the norm I wrote ||f|| = \sqrt{(([vcos])^2 + ([vsin])^2} since that would make it always positive. When I used the parallelogram law, I used x = vcos(theta) and y = vsin(theta). However, I clearly defined the dorm wrong since I got that the two sides of the equation equaled each other.

Is there another way to define a norm? Am I choosing x and y in the parallelogram law wrong?
 
Last edited:
Physics news on Phys.org
hi norm! :biggrin:

i don't understand what you're doing :confused:

if eg f(x) = x, g(x) = -x, then ||f+g|| = 0, but ||f|| = ||g|| = b :smile:
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 43 ·
2
Replies
43
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K