- #1

Master1022

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- 117

- Homework Statement
- Find the short circuit current and hence the Norton equivalent circuit.

- Relevant Equations
- V = IR

**My question is:**What is wrong with my working/ method (in the attached pictures) to find [itex] i_{sc} [/itex]? I can get the Norton equivalent from there, but seem to get the same answer as the solution scheme.

Context: we are given the circuit depicted in the picture (initially with no connection between the [itex] V_{out} [/itex] nodes) and the question is building up to us finding the Norton equivalent circuit. From the previous parts, we have shown:

- [itex] V_1 = \frac{20}{9} V_{out} [/itex] for the open circuit condition

- [itex] V_{out} = 4.5 [/itex] Volts

The answer uses the method of setting the sources to 0, but we have been told (in lectures) that method is not valid when there are dependent current sources.

I have asked a peer and they suggested that the error may lie in the fact that I let [itex] V_{out} = 0 [/itex] volts, but I cannot see why that is the error.

I have attached two versions of the working, but hopefully, it is legible.

I would appreciate any help.

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