- #1

zenterix

- 555

- 76

- Homework Statement
- Plot the ##i_A## vs ##v_A## characteristics for the nonlinear network shown in Fig. 4.49. Assume the diode is ideal.

- Relevant Equations
- ##i_D = I_s\left (e^{v_D/v_{TH}}-1\right )## (Diode)

I am quite stumped here.

This is what I did so far.

1) The first thing I did was to forget about the terminals to the left and the diode, and to write the circuit as a Thevenin equivalent circuit. Then I put in the diode. However, the terminals we are interested in are lost when we do this.

2) I then tried using the node method as follows

Here is the v-i relationship for the diode

##i_D=I_S\left (e^{\frac{e_1-e_2}{v_{TH}}}=1\right )##

and here is KCL applied to the ##e_1## node

##i_A-i_D-\frac{e_1}{10^3}=0##

##i_A-i_D=\frac{v_A}{10^3}##

We also have the v-i relationship for the resistors

##\frac{e_2-1}{10^3}=i_D##

##\frac{-e_1}{10^3}=i_D##

I'm a bit stumped at this point.