Subtracting 2 Fractions with Variables to Exponents: Explained

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SUMMARY

The forum discussion centers on the mathematical expression -2((1/((x^2 + 1)^2 )) - ((4x^2 )/(x^2 +1)^3 )) = 6x^2 - 2/(x^2 + 1). Participants clarify the correct interpretation of the expression, emphasizing the importance of parentheses in mathematical notation. A key point raised is the distinction between (6x^2 - 2)/(x^2 + 1) and 6x^2 - 2/(x^2 + 1), which significantly alters the meaning of the equation. The discussion highlights the necessity of precise notation in algebraic expressions involving fractions and variables.

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Tubefox
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-2((1/((x^2 + 1)^2 )) - ((4x^2 )/(x^2 +1)^3 )) = 6x^2-2/(x^2+1)


This is actually the last step of this problem. I understand everything they did up until here, but I'm a bit confused as to how they got from their last step, to the actual answer. Could someone explain?
 
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Are you missing a '-' in front of the coefficient of the x^2 term and should that be (x^2+1)^3 ?
 


Tubefox said:
-2((1/((x^2 + 1)^2 )) - ((4x^2 )/(x^2 +1)^3 )) = 6x^2-2/(x^2+1)


This is actually the last step of this problem. I understand everything they did up until here, but I'm a bit confused as to how they got from their last step, to the actual answer. Could someone explain?

Don't you mean (6x^2 - 2)/(x^2 + 1)? You wrote 6x^2 - 2/(x^2+1), which is a completely different thing.

RGV
 

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