Not only is the symbol daunting, but the words are too

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This is probably another stupid question.

Since M3 states the same condition, it would be wrong/unnecessary to even do 0*1 = 0 because it contradicts M4 \ {0} right?
 
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micromass said:
M3 does not state the same thing as M4...

But they have a similar condition...
 
Oh wait you know what, never mind. I was looking at 2.49 and I thought [tex]0^{-1} = 0[/tex] and I had to test [tex]0*1 = 0[/tex].

So yes I do need to test 0*1 = 0 for x =0