Not sure about my solution (fictionless Pulley)

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SUMMARY

The discussion centers on calculating the acceleration of two masses, m and 2m, hanging from a frictionless pulley. The initial calculation presented indicates that the acceleration a is derived as a = g/3, based on the net force and total mass. However, a more robust approach is recommended, utilizing Newton's 2nd law to set up separate force equations for each mass, which will also yield the string tension alongside the acceleration.

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Masses m and 2m hang from opposite ends of a string passing over a light,
frictionless pulley. What is their acceleration?




I said that the total unblalance force on the two objects is 2mg-mg=mg and the total mass is 2m+m=3m

So the acceleration a is a=mg/3m=g/3

Is this right? could somebody check it for me please? thanks :redface:
 
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You are correct. But why not check it yourself, by using a more general method: Set up force equations (Newton's 2nd law) for each mass separately and combine the two equations. That will allow you to solve for both the acceleration and the string tension.
 
Ok that makes sense ^_^ I'll try it. thanks again
 

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