Nuclear Beta Decay (Parity, deta[L])

  • Thread starter qwerty2010
  • Start date
  • #1
I do not get the concepts of the parity change and how do I find the deta (l) for beta decay.
Please Help!!

Classify the following decays according to their degree of forbiddenness, all ground states decays.

89Sr (5/2+) -> 89Y (1/2-)
26Al (5+) -> 26Mg (2+)
97Zr (1/2+) -> 97Nb (1/2-)

What are theirs change in parity and deta (L)?
How do you calculate it? Thanks again!
 

Answers and Replies

  • #2
Hey, I don't quite remember this but I'll try to explain how you do it for your first reaction.

At the beginning, you can find the allowed values for L ( the orbital angular momentum ) via the angular momentum addition theorem: L = { |J1-J2|,..,|J1+J2|} in integer steps.

As for the parity, for the 1st example you see that there is a change of parity: 5/2+ goes to 1/2-. This will have an effect on the allowed values of L. For parity to be conserved, you need to have:

parity(Sr) = parity(Y)*parity(L).

parity(L)= (-1)^L
Hence you can see that only L=3 works here.
While doing this, I have assumed a Fermi transition ( the electron & neutrino have opposite aligned spins ).

If they for example they have parallel aligned spins, the transition will be Gamow-Teller and for the allowed values of L you will get only 2 ( you subtract 1 from all the values you got for the allowed values of L you got from the addition theorem ).

So that's it I think. Your transition is 3rd forbidden pure Fermi.

Now try for the next two examples and see if it matches with your school work.
 

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