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I did say that...QuantumPion said:Not even, keep in mind the capacity factor of solar is like 15% while nuclear is >90%.
I did say that...QuantumPion said:Not even, keep in mind the capacity factor of solar is like 15% while nuclear is >90%.
nikkkom said:Some projects fail, others already generate power.
Check these on Wikipedia:
Agua Caliente Solar Project
Installed capacity 250 MW, maximum planned 397 MW
California Valley Solar Ranch
Installed capacity 22 MW (Oct 2012), maximum planned 250 MW
Copper Mountain Solar Facility
Installed capacity 150 MW, maximum 418 MW
Catalina Solar Project
Installed capacity 60 MW, maximum 143 MW
Mesquite Solar project
Installed capacity 150 MW, maximum 700 MW
Use the map link to see them in Google Maps with your own eyes. Gives quite a perspective on their size, simplicity, and the vast areas of undeveloped desert available for expansion.
This is really happening, despite eco-nazis' attempts to return us to life in caves.
You just refuse to read the writing on the wall.
The Mesquite Solar project has the Palo Verde nuclear power plant nearby (~5km NE), you can directly compare them. And the PV project is still growing.nikkkom said:Apparently this part is being willfully ignored:
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Use the map link to see them in Google Maps with your own eyes. Gives quite a perspective on their size, simplicity, and the vast areas of undeveloped desert available for expansion.
"""
mfb said:The Mesquite Solar project has the Palo Verde nuclear power plant nearby (~5km NE), you can directly compare them. And the PV project is still growing.
HowlerMonkey said:I'm for safe nuclear power.
In that, I mean reactors that don't have to be continually fed power to keep them from burning up.
A reactor were designed with a convective cooling loop that could tolerate not having the grid or diesel generators would be fine with me.
Anything less is just tempting fate.
NPPs are pretty inefficient, but that doesn't have anything to do with why they need outside power.jadair1 said:If NPP are so efficient why do they need outside power to keep them going...
You have the issue backwards in two different ways:...shouldn't they be able to provide their own electricity if outside power is lost and the reactors have not scrammed?
russ_watters said:NPPs are pretty inefficient, but that doesn't have anything to do with why they need outside power.
For the most part all of our current Power Generating Systems are pretty innefficient, I don't think I can think of one that has close to 20% efficiency.
The reason they need outside power is for when the plant isn't generating its own power to run its cooling systems.
My problem with this is that most NPP facilities have multiple reactors so there would be no reason to have them all ofline at the same time unless it was a catastrophic failure such as Fukushima was.
Of course when a plant is connected to the grid the power can run either way when needed..
It sounds like you think nuclear plants are net users of electricity, not generators!
No, I do not think that, not at all. I believe they are very ineficient and ony exist to produce plutonium for the war machine but that is a different conversation.
You have the issue backwards in two different ways:
1. If there is no connection to the grid, there is nowhere for the heat generated by the plant to go. It has to shut down to prevent overheating if it is not generating electricity for the grid.
Do you mean there is no way to shed heat if they are not producing electricity?
Can they not continue to run the turbines and shunt the electricity produced somewhere, perhaps banks of resistors and capacitors and bled to ground if need be, this seems like a simple design flaw to me.
2. As a matter of safety, a nuclear plant must have several backups and when backups are lost, they are shutdown whether they really need to be or not.
The first backup would be the other reactors that are online, if all reactors go offline due to an accident, (a very uncommon event I believe it has only happened once), then the secondary source would be the grid and the tertiary source would be the diesal generators onsite.
That's exactly my point.Argentum Vulpes said:And how does 700MW compare with 3.3GW?
Er, no - the only kind that is that inefficient is solar power. All the rest are more efficient.jadair1 said:For the most part all of our current Power Generating Systems are pretty innefficient, I don't think I can think of one that has close to 20% efficiency.
Oy. That's basically conspiracy theory. Why don't you google the efficiency of a few different types of power plants, starting with nuclear.No, I do not think that, not at all. I believe they are very ineficient and ony exist to produce plutonium for the war machine but that is a different conversation.
Of course there is: you run pumps and the cooling tower. But to run pumps while not producing electricity, you need to get electricity from your backup generators or the grid.Do you mean there is no way to shed heat if they are not producing electricity?
A bank of resistors still produces heat that needs to be dissipated, but you're still missing the point: the generation system itself can fail. That's precisely what happened at Three Mile Island - and while the other reactor on site was down for refueling:Can they not continue to run the turbines and shunt the electricity produced somewhere, perhaps banks of resistors and capacitors and bled to ground if need be, this seems like a simple design flaw to me.
russ_watters said:It seems like you have a lot of severe misunderstandings about nuclear and conventional power generation that make almost everything you think you know wrong!
itachi Power Groupjadair1 said:http://www.mpoweruk.com/energy_efficiency.htm
Nuclear
The efficiency of nuclear plants is little different. On the steam turbine side they use the Rankine thermodynamic cycle with steam temperatures at saturated conditions. This gives a lower thermal cycle efficiency than the high temperature coal fired power plants. Thermal cycle efficiencies are in the range of 38 %. Since the energy release rate in nuclear fission is extremely high, the energy transferred to steam is a very small percentage - only around 0.7 %. This makes the overall plant efficiency only around 0.27 %. But one does not consider the fuel efficiency in nuclear power plants; fuel avaliabity and radiation losses take center stage
...
So my memory is failing me, I have not looked at these things for many years and I got an off the top of my head number wrong.
But if you look at the table I linked to you will see that Nuclear is the least efficient of all the major conventional power sources. Not to mention the 99.3% of the energy that is not converted to steam in a NPP, can you imagine if that wasted energy could be harvested in some way.
Exactly. If I would have a way to generate infinite amounts of antimatter without costs (both money and energy), and if I can use them in a power plant with 10% efficiency, I don't care about that value at all. To generate more power, I would just produce and burn more antimatter.QuantumPion said:However this is simply the thermodynamic efficiency of the plant in terms of how many MW-electrical are generated for each MW-thermal produced and has nothing to do with economic efficiency (uranium is much cheaper than coal therefore it is not an apples-to-apples comparison).
jadair1 said:Nuclear
The efficiency of nuclear plants is little different. On the steam turbine side they use the Rankine thermodynamic cycle with steam temperatures at saturated conditions.
This gives a lower thermal cycle efficiency than the high temperature coal fired power plants.
Thermal cycle efficiencies are in the range of 38 %.
Since the energy release rate in nuclear fission is extremely high, the energy transferred to steam is a very small percentage - only around 0.7 %.
This makes the overall plant efficiency only around 0.27 %.
But one does not consider the fuel efficiency in nuclear power plants; fuel availability and radiation losses take center stage
gmax137 said:I don't know what the "radiation losses" are referring to.
Argentum Vulpes said:And how does 700MW compare with 3.3GW?
Again Nikkkom trying to cover the American southwest desert in PV panels will never work. Let's try something different, tell me how many sq miles you want covered in PV panels, and do a quick back of the envelope calculation.
1 kW per sq meter of land covered (best case)
44.7% efficacy of solar PV panel (best case, still in the lab)
And finally for kicks and giggles, how is power going to be supplied at night and made up during non peak times and days?
In the case of solar it will increasingly be mistake to point to large central installation as the sum all efforts, which neglects all the distributed residential, small projects. This source indicates US solar capacity will be 10 GWe by the end of the year, or about two nuclear reactor equivalents, with new solar coming on at a rate of another 4 GW per year at this time, i.e. a new reactor equivalent every year and half. One drawback of nuclear is that, if a utility starts planning for a new reactor today, their first power is probably 10 years away.russ_watters said:What is happening? All of those projects put together, if finished, will only equal the kW capacity of one nuclear plant and have a kWh capacity of about one sixth of a nuclear plant. That's still a long way from breaking out of the "other" category on a pie chart.
That's low by 2 or 3X. The one km^2 insolation is 1 GW, peak, as you say. Conversion minimum now is 15%, 20% on the expensive side, so 150 MW per km^2. Capacity factor in Arizona is 25% (6 kWh insolation per m^2 per day). Resulting daily average power is then 30 MW/km^2. Call it 20 MW/km^2 with wasted land. US average power load is ~430 GWe, which is supplied then by ~22e3 km^2 of PV, or 150 km on a side, a tiny parcel of what's called the US southwest.nikkkom said:I did it on this forum already about a year ago. Be my guest:
Insolation: ~1kW/m^2
PV efficiency: growing by the day, but let's assume conservatively that it will never exceed 10% for economically viable multi-km^2 installations.
Losses due to night / clouds / rain: 4/5, but let's assume higher losses: 9/10.
Thus, 1 m^2 can produce only 10W on average. 1 km^2 can produce 10 MW.
I guess the problem is that at the moment, there are more commercially advantageous ways of making electricity. Maybe in a few years when fossil fuels run out, such projects will be commercially more viable (as well as nuclear power). But ideally we wouldn't want to use all our fossil fuels and pollute the world that much with them. So then the problem is if we can motivate ourselves enough to choose the less commercially viable options, and/or to invest more into research into making green technologies more commercially viable.mfb said:...and then it gets night and you try to use your average 897 GW to operate a single light bulb.
The US has certainly enough desert area for PV. Assuming those deserts are suitable for it (I don't know which fraction will have issues with sand). But then you still have the high costs and the storage issue. And many countries don't have so many deserts.
mfb said:Exactly. If I would have a way to generate infinite amounts of antimatter without costs (both money and energy), and if I can use them in a power plant with 10% efficiency, I don't care about that value at all. To generate more power, I would just produce and burn more antimatter.
jadair1: please surround quotes with [noparse][/noparse]-tags. Don't pretend that this text is from you.
gmax137 said:True enough. Most nukes do make saturated steam. There are reactor designs that produce superheated steam, but not like a modern coal-burner.
True.
True. That means 38% of the reactor core power leaves as electrical megawatts. The rest goes out through the cooling towers. The coal stations do the same thing, only it's more like 45% of the boiler power goes out as electric power.
False. All of the heat generated in the fuel is transferred to the steam (otherwise, the core would heat up continuously). I'm baffled by what this is trying to say. It doesn't make any sense.
Gibberish. See above.
Partly true - reactor fuel is considerably cheaper than fossil fuel in terms of $/Btu. That's one reason why it is worth the extra capital cost to build a nuclear unit. That doesn't mean the nuclear operators don't care about fuel cost, they do. But it isn't the dominating consideration that it is for the gas-burner or coal-burner. And that's why the fossil fuel interests (the gas drillers and coal mine owners) are so opposed to nuclear power. It cuts them out of the gravy train.
I don't know what the "radiation losses" are referring to.
QuantumPion said:I'm guessing neutrinos but I don't think he really knows what he's talking about, he is mixing up different concepts.
I know it is getting redundant, but again I must point out that those numbers don't consider the low capacity factor or need for backup. Right now the need for backup can be ignored since the solar capacity is so low, but if it ever reaches a meaningful level, solar plants will basically all need identically sized natural gas plants built next door.mheslep said:In the case of solar it will increasingly be mistake to point to large central installation as the sum all efforts, which neglects all the distributed residential, small projects. This source indicates US solar capacity will be 10 GWe by the end of the year, or about two nuclear reactor equivalents, with new solar coming on at a rate of another 4 GW per year at this time, i.e. a new reactor equivalent every year and half.
jadair1 said:Sorry, that was not me talking it was quotes from Hitachi and the article I provided the link to, I thought that was clear.
Apparently it was not.
gmax137 said:That's no problem, jadair, I was responding point by point to the posted text; it doesn't matter to me who wrote it. I'm not attacking you in any way - I'm just trying to shed light on these subjects.
Yes they do; I include the capacity factor for http://rredc.nrel.gov/solar/pubs/redbook/PDFs/AZ.PDF: 25% or 6 kWh/m^2 out of a 24 hour day (that's measured over many years: winter/summer, night/day, sunny/cloudy). At 100% CF we'd be talking about 150 MW/km^2 (total ~2900 km^2) instead of the 20-30 MW/km^2 (~22000 km^2).* I was mostly addressing Argentum Vulpes' comment that one would have to "cover" over the southwest US to supply the US load w/ solar PV. Hardly.russ_watters said:I know it is getting redundant, but again I must point out that those numbers don't consider the low capacity factor
True, no backup calculation nor transmission from the dessert. Both are requirements to go mainstream w/ solar I agree, but the calculation above is just for land sufficient to supply average power. That is, the land calculation includes enough solar to produce, during sunshine, four times the average long term load and thus assumes storage to hold the extra. Storage will take some more space but not a significant share of the solar collection area. The present problem with storage is of course cost, and I expect will be for some time.or need for backup.
Agreed. That seems to be what's coming at least initially. The new ~.7GW solar thermal plant, Ivanhoe, is a hybrid with natural gas hookup to fire its boiler absent sun.Right now the need for backup can be ignored since the solar capacity is so low, but if it ever reaches a meaningful level, solar plants will basically all need identically sized natural gas plants built next door.
D H said:CNN is broadcasting a documentary on nuclear power tonight. Knowing CNN, they'll bend over backwards to present both sides of the issue.