Nuclear Fusion Rate: Calculating Reaction Speed & Energy

Click For Summary
Nuclear fusion, specifically Deuterium-Tritium fusion, generates significant energy, approximately 3.4 * 10^14 J/kg. The reaction rate can be calculated using the densities of deuterium and tritium, along with the temperature, with a typical example showing a reactivity rate of about 10^-22 m^3/s at 100 million Kelvin. By multiplying the densities and the reactivity rate, one can estimate the number of reactions per cubic meter per second, which in this case is around 10^8 reactions/m^3/s. However, this rate is insufficient for practical reactor applications. For further research, it's recommended to explore various reactor publications and resources for detailed plasma density information.
Nivek Writer
Messages
7
Reaction score
0
Hello everyone,

I have a question about nuclear fusion.
Deuterium-Tritium fusion generates 3.4 * 1014 J/kg when you have a
mixture of around 400 grams of deuterium and 600 grams of tritium.
My question is: what is the rate at which this fusion reaction takes place?
Is there a formula for the fusion rate and what is the reaction speed at, for example, 100 million Kelvin?
I am in high school and I am doing research on nuclear fusion. I was able to calculate the amount of energy released per kg, but I don't know how to calculate the rate at which this reaction takes place depending on the temperature (in kg per m^3 per second).
 
Physics news on Phys.org
mfb said:
There are calculations, sure. Fusion rate depends on both temperature and pressure (or particle density).
Wikipedia, as usual, has details.
I have read the Wikipedia page, but I don't know for sure if I fully understand how the formula works.
Could you please give an example of a calculation?
 
If you know densities and temperature, you can just plug in numbers.
Let's say we have 1015/m3 D and 1015/m3 T at a temperature of 100 million K. The reactivity rate, from the plot, is about 10-22 m3/s.
Multiply everything together, and you get 1015/m3 * 1015/m3 * 10-22 m3/s = 108/(m3*s) reactions. Not enough for a reactor, but I just made up those plasma density numbers.
 
mfb said:
If you know densities and temperature, you can just plug in numbers.
Let's say we have 1015/m3 D and 1015/m3 T at a temperature of 100 million K. The reactivity rate, from the plot, is about 10-22 m3/s.
Multiply everything together, and you get 1015/m3 * 1015/m3 * 10-22 m3/s = 108/(m3*s) reactions. Not enough for a reactor, but I just made up those plasma density numbers.

Thanks for the explanation. I understand it now.
 
mfb said:
If you know densities and temperature, you can just plug in numbers.
Let's say we have 1015/m3 D and 1015/m3 T at a temperature of 100 million K. The reactivity rate, from the plot, is about 10-22 m3/s.
Multiply everything together, and you get 1015/m3 * 1015/m3 * 10-22 m3/s = 108/(m3*s) reactions. Not enough for a reactor, but I just made up those plasma density numbers.

Is there a formula or a website where you can find the number density of plasma?
 
You can check the websites, publications and other pages of/about various reactors. You are supposed to do the research.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K