Nuclear / Particle Phys Notation quick q spin, parity,J

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SUMMARY

The discussion centers on the notation used in nuclear and particle physics, specifically regarding the symbols ##J^{\pm}##, which represent total angular momentum and spin. Participants clarify that ##J## denotes total angular momentum, while ##s## represents spin. The parity is defined as ##P=(-1)^{l}##, contrasting with some sources that state ##P=(-1)^{spin}##. The notation ##^{J} l_{symbol s}## is explained, where ##J## is total angular momentum, ##s## is spin, and ##l_{symbol}## corresponds to orbital angular momentum values such as ##s,p,d,f##.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly angular momentum.
  • Familiarity with particle physics notation and terminology.
  • Knowledge of parity and its mathematical representation.
  • Basic grasp of quantum states and their representations.
NEXT STEPS
  • Study the concept of total angular momentum in quantum mechanics.
  • Research the implications of parity in particle interactions.
  • Explore the differences between spin and orbital angular momentum.
  • Examine examples of quantum state notation in various particle physics contexts.
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Students and researchers in nuclear and particle physics, educators teaching quantum mechanics, and anyone seeking to clarify the notation and concepts related to angular momentum and parity.

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Homework Statement


When we use ##J^{/pm} ## where ##/pm## gives the parity, some sources say ##J## is the spin and some say the total angular momentum, I'm confused !

Also in my notes we have ##P=(-1)^l##, but looking on this thread: https://www.physicsforums.com/threads/quick-question-about-spin-parity-j-p-notation.455873/ it has ##P=-1^{spin}##.?

Also confused with some other notation.. when we write ## ^{J} l_{symbol _s}##, where ##J## is the total angular momentuum, ##s## is the spin and ##l_{symbol}## is ##s,p,d,f..## corresponding to ##l=0,1,2...##.

So looking at things such as ##^{3}D_{1}## I see we have ##l=2, s=1, J=3## and we know ##J=(l+s)+...+##modulus of ##(l-s)##*

BUT looking at ##^{3}S_{1}## we have ##l=0,s=1,J=3## . Which I'm confused how you get ##J=3## from *..

Thanks in advance..
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