MHB Null Column Vector vs $ |0 \rangle$

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There is no difference between a 'null column vector' and the ket notation $ |0 \rangle $ in the standard matrix interpretation. Kets represent column vectors, while bras are their complex conjugate transposes, functioning as row vectors. However, distinctions may arise in infinite-dimensional Hilbert spaces. Understanding these nuances is essential for advanced applications in quantum mechanics. The discussion highlights the importance of context in mathematical interpretations.
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Hi - is there any difference between 'null column vector' and $ |0 \rangle $? Ta
 
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There's no difference in the usual matrix interpretation of bras and kets. Kets are column vectors, and bras are complex conjugate tranposes, so they're row vectors. This does change in infinite-dimensional Hilbert space.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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