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PhysicsTest

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- Homework Statement:
- A certain photo surface has a spectral sensitivity of 6mA/W of incident radiation of wavelength 2,537 A. How many electrons will be emitted photoelectrically by a pulse of radiation consisting of 10,000 photons of this wavelength?

- Relevant Equations:
- ##\lambda=\frac{1.24} {E_G}##

Spectral response : ##\lambda=\frac{1.24} {E_G}## ->eq(1)

Given, ##\lambda = 2537 * 10^{-10} m = 0.2537\mu m ##

##E_G = \frac{1.24} {\lambda} = \frac{1.24} {0.2537} = 4.88 eV##

So, i can assume if 10,000 photons illuminate then 10000 electrons will be emitted. But i am mainly confused with the value of 6mA/W. I think need to convert it into eV to know the cutoff wavelength at which the electron can be excited?

Given, ##\lambda = 2537 * 10^{-10} m = 0.2537\mu m ##

##E_G = \frac{1.24} {\lambda} = \frac{1.24} {0.2537} = 4.88 eV##

So, i can assume if 10,000 photons illuminate then 10000 electrons will be emitted. But i am mainly confused with the value of 6mA/W. I think need to convert it into eV to know the cutoff wavelength at which the electron can be excited?