Number of Real Solutions for Trigonometric Equation

Click For Summary
SUMMARY

The equation $\sin (\sin (\sin x)) = \cos (\cos (\cos x))$ has exactly 2 real solutions within the interval $0 \leq x \leq 2\pi$. This conclusion is derived from analyzing the behavior of the sine and cosine functions, particularly their nested forms. The periodic nature of these trigonometric functions contributes to the determination of the number of intersections within the specified range.

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Familiarity with the concept of periodicity in functions
  • Knowledge of solving equations involving nested functions
  • Basic skills in graphing functions to visualize intersections
NEXT STEPS
  • Study the properties of nested trigonometric functions
  • Learn about graphical methods for finding intersections of functions
  • Explore the implications of periodicity in trigonometric equations
  • Investigate numerical methods for solving transcendental equations
USEFUL FOR

Mathematicians, students studying trigonometry, and anyone interested in solving complex trigonometric equations.

juantheron
Messages
243
Reaction score
1
Number of real solution of the equation $\sin (\sin (\sin x)) = \cos (\cos (\cos x))$

where $ 0 \leq x\leq 2\pi$
 
Mathematics news on Phys.org
jacks said:
Number of real solution <--- 2
of the equation $\sin (\sin (\sin x)) = \cos (\cos (\cos x))$

where $ 0 \leq x\leq 2\pi$

...
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
2K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K