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Number of real solution of the equation $\sin (\sin (\sin x)) = \cos (\cos (\cos x))$
where $ 0 \leq x\leq 2\pi$
where $ 0 \leq x\leq 2\pi$
The equation $\sin (\sin (\sin x)) = \cos (\cos (\cos x))$ has exactly 2 real solutions within the interval $0 \leq x \leq 2\pi$. This conclusion is derived from analyzing the behavior of the sine and cosine functions, particularly their nested forms. The periodic nature of these trigonometric functions contributes to the determination of the number of intersections within the specified range.
PREREQUISITESMathematicians, students studying trigonometry, and anyone interested in solving complex trigonometric equations.
jacks said:Number of real solution <--- 2
of the equation $\sin (\sin (\sin x)) = \cos (\cos (\cos x))$
where $ 0 \leq x\leq 2\pi$