Number of Roots Using Rouche Theorem

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SUMMARY

The discussion centers on applying Rouche's Theorem to determine the number of roots for the polynomial function f(z) = z^n + a_{n-1}z^{n-1} + ... + a_0 within the unit circle |z| < 1. The argument presented incorrectly assumes |f| > |g|, where g(z) = - a_{n-1}z^{n-1} - ... - a_0. A counterexample using f(z) = z^2 + 2 illustrates the flaw in this reasoning, as it fails to satisfy the conditions of Rouche's Theorem. Thus, the conclusion that the number of roots of f is equal to n is invalid without proper justification of the inequality.

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ksuer
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Problem: find number of roots of z^n + a_{n-1}z^{n-1} + ... + a_0, |z| &lt; 1

What is wrong with this argument:
Let f(z) = z^n + a_{n-1}z^{n-1} + \cdots + a_0, and g(z) = - a_{n-1}z^{n-1} - ... - a_0. Then, |f| > |g| and f+g = z^n. by Rouche thm, number of roots of f is equal to number of roots of f + g, which is n.
 
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How do you get |f| > |g| ? Try the argument for f(z)=z^2 +2.
 

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