Number Theory. If d=gcd(a,b) then

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SUMMARY

The discussion focuses on proving that if \( d = \text{gcd}(a, b) \), then \( \text{gcd}\left(\frac{a}{d}, \frac{b}{d}\right) = 1 \). The key insight is that demonstrating 1 as a linear combination of \( \frac{a}{d} \) and \( \frac{b}{d} \) is essential to establish their coprimality. The approach involves recognizing that dividing both \( a \) and \( b \) by their greatest common divisor \( d \) simplifies the problem to showing that the resulting integers share no common factors other than 1.

PREREQUISITES
  • Understanding of the Euclidean algorithm for computing gcd
  • Familiarity with linear combinations in number theory
  • Basic knowledge of integer properties and divisibility
  • Concept of coprime numbers
NEXT STEPS
  • Study the Euclidean algorithm for finding gcd in detail
  • Learn about linear combinations and their applications in number theory
  • Research properties of coprime integers and their significance
  • Explore proofs related to gcd and divisibility in integers
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Students studying number theory, mathematicians interested in gcd properties, and anyone seeking to deepen their understanding of linear combinations and coprimality in integers.

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Homework Statement


If d=gcd(a,b) show that gcd((a/d),(b/d))=1



Homework Equations


N/A?



The Attempt at a Solution


Basically, I know that I need to show that 1 is a linear combination of a/d and b/d. I'm not exactly sure how to go about this. Dividing by d gives (d/d)=1=gcd(a/d,b/d) if that's correct, does that get me anywhere?
 
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If d = gcd(a,b), then what does that imply about linear combinations of a and b?
 

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