NxN-complex matrix, identified 2Nx2N-real matrix, determinant

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The discussion centers on the determinant of a 2N×2N matrix constructed from a complex N×N matrix A, specifically the matrix formed by the real and imaginary parts of A. It is proposed that the determinant of this 2N×2N matrix could be expressed as the squared magnitude of the determinant of A, leading to the conjecture that det(Re(A) - iIm(A)) equals |det(A)|^2. A brute force computation supports this conjecture, showing a relationship between the determinants of the real and complex matrices. The conclusion affirms that the determinant of the constructed matrix is indeed equal to the square of the magnitude of the determinant of the original complex matrix. This finding is significant for identifying N-dimensional complex space with 2N-dimensional real space.
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If A\in\mathbb{C}^{N\times N} is some complex matrix, is there anything we could say about the determinant of the matrix

<br /> \left(\begin{array}{cc}<br /> \textrm{Re}(A) &amp; -\textrm{Im}(A) \\<br /> \textrm{Im}(A) &amp; \textrm{Re}(A) \\<br /> \end{array}\right)\quad\in\mathbb{R}^{2N\times 2N}<br />

where \textrm{Re}(A)\in\mathbb{R}^{N\times N} and \textrm{Im}(A)\in\mathbb{R}^{N\times N} have been defined by element wise real and imaginary parts?

For example, could it be that the determinant of the 2N\times 2N-matrix could be expressed as function of the determinants of the real N\times N-matrices?

Or is the asked determinant related to the complex determinant \det(A)\in\mathbb{C}?

I'm interested in this, because if I want to identify N-dimensional complex space with 2N-dimensional real space, then the complex linear transformation is naturally identified with the above matrix. The equation

<br /> z^2 = Az^1,\quad\quad z^1,z^2\in\mathbb{C}^N<br />

is equivalent with

<br /> \left(\begin{array}{c}<br /> \textrm{Re}(z^2) \\ \textrm{Im}(z^2) \\<br /> \end{array}\right)<br /> = \left(\begin{array}{cc}<br /> \textrm{Re}(A) &amp; -\textrm{Im}(A) \\<br /> \textrm{Im}(A) &amp; \textrm{Re}(A) \\<br /> \end{array}\right)<br /> \left(\begin{array}{c}<br /> \textrm{Re}(z^1) \\ \textrm{Im}(z^1) \\<br /> \end{array}\right)<br />
 
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a conjecture

I computed by brute force the following formula:

<br /> \textrm{det} \left(\begin{array}{cccc}<br /> R_{11} &amp; R_{12} &amp; -I_{11} &amp; -I_{12} \\<br /> R_{21} &amp; R_{22} &amp; -I_{21} &amp; -I_{22} \\<br /> I_{11} &amp; I_{12} &amp; R_{11} &amp; R_{12} \\<br /> I_{21} &amp; I_{22} &amp; R_{21} &amp; R_{22} \\<br /> \end{array}\right)<br />
<br /> = \textrm{det}(R)^2 + \textrm{det}(I)^2 + (R_{11}I_{22} - R_{21}I_{12})^2 + (R_{22}I_{11} - R_{12}I_{21})^2<br /> + 2(R_{11}I_{21} - R_{21}I_{11})(R_{22}I_{12} - R_{12}I_{22})<br />
<br /> = \textrm{det}(R - iI) \textrm{det}(R + iI)<br />

So it seems that

<br /> \textrm{det}\left(\begin{array}{cc}<br /> \textrm{Re}(A) &amp; -\textrm{Im}(A) \\<br /> \textrm{Im}(A) &amp; \textrm{Re}(A) \\<br /> \end{array}\right) = |\textrm{det}(A)|^2<br />

could be true for all A\in\mathbb{C}^{N\times N}.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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