Object oscillates such that displacement is x = (.222)sin(314t)

[jorgegalvan93]

Homework Statement

Object is oscillates such that displacement is x = (.222)sin(314t), where t is in seconds.
In one period, the objects moves what distance?

Homework Equations

What is the relationship between displacement, amplitude and distance?

The Attempt at a Solution

The amplitude is the 0.222 m, so the displacement is four times that, as it moves from the centre to the edge, back to the centre, to the other edge and then back to the centre again, so the object moves 0.888 m. but WHY?

 

[berkeman]

Homework Statement

Object is oscillates such that displacement is x = (.222)sin(314t), where t is in seconds.
In one period, the objects moves what distance?

Homework Equations

What is the relationship between displacement, amplitude and distance?

The Attempt at a Solution

The amplitude is the 0.222 m, so the displacement is four times that, as it moves from the centre to the edge, back to the centre, to the other edge and then back to the centre again, so the object moves 0.888 m. but WHY?

I think you explained it quite well (I bolded your solution). Is there something about that explanation that you are not getting?

 

[rock.freak667]

If you consider the graph of x=0.222sin(314t) for one period.

Then if you consider the distances covered in going from 0 to max, max to 0 and back, then you will get 4*Amplitude.

Which is exactly what you explained, but I don't know if you wanted to know with respect to the graph/equation.