Object Thrown Vertically Upward

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SUMMARY

A ball is thrown vertically upward with an initial speed of 20.0 m/s. To determine its speed at a height of 16 m, the kinematic equations of motion are applied, specifically using the acceleration due to gravity (g = -9.81 m/s²). The time required to reach this height can be calculated using the equation d = v0t + (1/2)gt². The discussion highlights that there are two possible speeds at 16 m due to the ball's ascent and descent phases.

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  • Understanding of kinematic equations
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  • Basic algebra for solving equations
  • Concept of free fall and projectile motion
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1. Homework Statement :

A ball is thrown vertically upward with a speed of 20.0m/s.

i) How fast is it moving when it reaches 16m
ii) How long is required to reach this height?
iii) Explain why there are two answers.
2. The attempt at a solution
I assume there are two vectors. The force of the ball going upwards and the force of gravity pulling the ball downwards.


Thanks in advance for helping.
 
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There is no force upwards because the ball is in free flight. Therefore the only force is due to gravity.

Using a=g you can derive all the formula you need by integrating wrt time:

a=g
v=v0+g*t
d=v0t+(1/2)*g*t^2
 

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