Oblique Impact of Smooth Spheres

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SUMMARY

The discussion centers on the oblique impact of two spheres, where a sphere of mass m collides with a stationary sphere of mass M, with a coefficient of restitution e. The key conclusion is that if m equals eM, the resulting directions of motion after impact are at right angles. The equations of motion derived include momentum conservation and the restitution condition, leading to the realization that the velocities V1 and V2 must be treated as vector components to demonstrate the right-angle relationship post-impact.

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  • Basic knowledge of vector components in two-dimensional motion
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SpartaGhost
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Hey, I'm struggling with this question, any help would be great.

A sphere of mass m impinges obliquely on a sphere of mass M, which is at rest. The coefficient of restitution between the spheres is e. Show that if m=eM, the directions of motion after impact are at right angles

My attempt was:

mUcosα = mV1 + MV2 (1)
V2-V1 = e(Ucosα) (2)

since m=eM
=> eMcosα = eMV1 + Mv2 then /m

so subtracting the equations gives
eUcosα = eV1 + V2
- eUcosα = V2 - V1

=> 0 = eV1 + V1
e = -1

which is where I just don't understand what to do now :(
 
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Well, if you want to show that " the directions of motion after impact are at right angles" you had better work with the directions of motion hadn't you? Yet, I see no indication of x or y components. You see to be treating V1 and V2 as numbers- that is, assuming the two masses move in a straight line.
 
Hi, I used the parallel and perpendicular components and yeah the masses move in a linear direction.
 

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